已知:△ABC中,∠ACB=90°,AC=CB,D為直線BC上一動(dòng)點(diǎn),連接AD,在直線AC右側(cè)作AE⊥AD,且AE=AD.
(1)如圖1,當(dāng)點(diǎn)D在線段BC上時(shí),過點(diǎn)E作EH⊥AC于H,連接DE,求證:EH=AC;
(2)如圖2,當(dāng)點(diǎn)D在線段BC的延長線上時(shí),連接BE交CA的延長線于點(diǎn)M.求證:BM=EM;
(3)當(dāng)點(diǎn)D在射線CB上時(shí),連接BE交直線AC于M,若2AC=5CM,則
的值為
.