2.已知,過∠ECF內(nèi)一點(diǎn)A作AD∥/EC交CF于點(diǎn)D,作AB∥/CF交CE于點(diǎn)B.
(1)如圖1,求證:∠ABE=∠ADF;
(2)如圖2,射線BM,射線DN分別平分∠ABE和∠ADF,求證:BM∥DN;
(3)如圖3,在(2)的條件下,點(diǎn)G,Q在線段DF上,連接AG,AQ,AC,AQ與DN交于點(diǎn)H,反向延長AQ交BM于點(diǎn)P,如果∠GAC=∠GCA,AQ平分∠GAD,∠QAC=50°,求∠MPA+∠PQF的度數(shù).