3.已知,MN∥PQ,點(diǎn)A、點(diǎn)B分別在線(xiàn)段MN、PQ上.
(1)如圖1,點(diǎn)C在直線(xiàn)MN、PQ之間,求證∠ACB=∠NAC+∠QBC.
(2)如圖2,分別過(guò)點(diǎn)A和點(diǎn)C作直線(xiàn)AG,CH,使AG∥CH,以點(diǎn)B為頂點(diǎn)作直角∠DBl,2并且∠DBl的兩邊分別與直線(xiàn)CH、AG交于點(diǎn)F和點(diǎn)E,則∠CFB+∠AEB=
.(直接寫(xiě)出角度和)
(3)如圖3,在(2)的條件下,若BD和AE恰好分別平分∠CBQ和∠CAM,并且∠ACB=106°,求∠CFB的度數(shù).