1.如圖,正方形ABCD對角線交于O點(diǎn),過點(diǎn)O作線段EH,F(xiàn)G,分別交邊AB,BC,AD,DC于點(diǎn)E,F(xiàn),G,H,給出下列結(jié)論:
①若EF=GH,則EH⊥GF;
②若EH⊥GF,則EO=OF;
③若EO=OF,則EF
2+GH
2=EH
2;
④若EF
2+GH
2=EH
2,則EH
2=2AE
2+2CF
2.
上述結(jié)論中,所有正確結(jié)論的序號(hào)是( ?。?/div>
發(fā)布:2024/9/20 0:0:11組卷:86引用:1難度:0.5