m(CO
2)=6.6g,m(MgO)=8.0g,堿式碳酸鎂分解:aMgCO
3?bMg(OH)
2?cH
2O
(a+b)MgO+aCO
2↑+(b+c)H
2O↑,根據(jù)質(zhì)量守恒得:m(H
2O)=18.2g-6.6g-8.0g=3.6g,則m(MgO)═0.2mol,n(CO
2)═0.15mol,n(H
2O)═0.2mol,得:a:b:c=0.15:0.05:0.15=3:1:3,則堿式碳酸鎂的組成為3MgCO
3?1Mg(OH)
2?3H
2O
m(CO
2)=6.6g,m(MgO)=8.0g,堿式碳酸鎂分解:aMgCO
3?bMg(OH)
2?cH
2O
(a+b)MgO+aCO
2↑+(b+c)H
2O↑,根據(jù)質(zhì)量守恒得:m(H
2O)=18.2g-6.6g-8.0g=3.6g,則m(MgO)═0.2mol,n(CO
2)═0.15mol,n(H
2O)═0.2mol,得:a:b:c=0.15:0.05:0.15=3:1:3,則堿式碳酸鎂的組成為3MgCO
3?1Mg(OH)
2?3H
2O