如圖,已知△ABC為等腰直角三角形,∠BAC=90°,AB=AC.
(1)如圖1,點(diǎn)M是BC的中點(diǎn),點(diǎn)D在AB邊上,連接MD,過點(diǎn)M作ME⊥MD交AC于點(diǎn)E,連接AM,求證:AD=CE;
(2)如圖2,在(1)的條件下,過點(diǎn)A作AF∥MD交BC于點(diǎn)F,點(diǎn)G在AB邊上,連接CG交AF于點(diǎn)N,交DM于點(diǎn)H,若GA=GN,求證:CN=AE-CE;
(3)如圖3,已知點(diǎn)E在AC上,點(diǎn)D在BA延長線上且
,連接ED并以ED為邊向左側(cè)作等腰直角△DEH,且∠EDH=90°,DH=DE,點(diǎn)M為AC上一點(diǎn)且BC=2CM,當(dāng)MH取最小值時(shí)請直接寫出
的值.