2.觀察下列兩個(gè)等式:2×
=2
2-2×
-2,4×
=4
2-2×
-2,給出定義如下:我們稱使等式ab=a
2-2b-2成立的一對(duì)有理數(shù)a,b為“方差有理數(shù)對(duì)”,記為(a,b),如:(2,
),(4,
)都是“方差有理數(shù)對(duì)”.
(1)判斷數(shù)對(duì)(-1,-1)是否為“方差有理數(shù)對(duì)”,并說(shuō)明理由;
(2)若(m,2)是“方差有理數(shù)對(duì)”,求-6m-3[m
2-2(2m-1)]的值.